Write a C Program to Find the Roots of a Quadratic Equation by using if-else and else-if Statement

Statement of C Program: This Program finds all the Roots of a Quadratic Equation, for non-zero cofficients:

#include<stdio.h>

#include<conio.h>

#include<math.h>

main()

{

float A , B , C , root1 , root2;

float realp , imgp , disc;               
                                      /* realp stands for Real Part and imgp stands for Imaginary Part */

clrscr();

printf(" Enter the values of A , B and C\n");

scanf("%f%f%f" , &A , &B , &C);

if(A==0 || B==0 || C==0)

{

printf(" Error: Roots cannot be determined\n");

}

else

{

dis = (B * B) - (4 * A * C);

if(disc<0)

{

printf(" Imaginary Roots\n");

realp = -B/(2*A);

imagp = sqrt(abs(disc))/(2*A);

printf(" Root1 = %f + i%f\n" , realp , imagp);

printf(" Root2 = %f - i%f\n" , realp , imagp);

}

else if( disc == 0)

{

printf(" Roots are real and equal\n");

root1 = -B/(2 * A);

root2 = Root1;

printf(" Root1 = %f\n" , root1);

printf(" Root2 =%f\n" , root2);

}

else if(disc>0)

{

printf(" Roots are real and distinct\n");

root1 = (-B + sqrt(disc))/(2*A);

root2 = (-B - sqrt(disc))/(2*A);

printf(" Root1 = %f\n" , root1);

printf(" Root2 = %f\n" , root2);

}

}

}                                               /*  End of main()  */

Output1:

Enter the values of A , B and C

3 2 1

Imaginary roots

Root1 = -0.3333 + i0.471402

Root2 = -0.3333 - i0.471405

Output2:

Enter the values of A , B and C

1 2 1

Roots are real and equal

Root1 = -1.0000

Root2 = -1.0000

Output3:

Enter the values of A , B and C

3 5 2

Roots are real and distinct

Root1 = -0.666667

Root2 = -1.000000

                 

                                                              That's All !

                                   

Posted by Roky

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