C Program: Determine the Quadrant of point(x,y) by using AND Operator and else-if Statement

Function of scanf():

• scanf() is the Input Statement.  
• scanf() statement is used to give Input at the run time. 
• Format: scanf(" %f " , &a);
• In the above format 'a' is variable and value of 'a' is assigned at the run time. 
• In scanf() statement, character 'f ' indicates the format i.e ("  ");
  

Statement of C program: Enter the value of x and y and determine the quadrant of point(x,y) :

#include<stdio.h>

#include<conio.h>

void main()

{

float x,y ;

clrscr();

printf("Enter the value of x and y\n ");              //  \n  used for next line character.

scanf(" x=%f  y=%f" , &x , &y);                           

if (x>0 && y>0)                     // Both conditions must be True in order to execute the statement.

{

printf(" point(%f,%f) lies in Ist quad\n ,x,y");

}

else if (x<0 && y>0)

{

printf(" point(%f,%f) lies in IInd quad\n , x,y");

}

else if (x<0 && y<0)

{

printf(" point(%f,%f) lies in IIIrd quad\n ,x,y");

}

else if (x>0 && y<0)

{

printf(" point(%f,%f) lies in IVth quad\n , x,y");

}

else( x==0 && y==0)

{

printf("point(%f,%f) lies at the origin\n" ,x,y);

}

getch();

}

Output1:

Enter the value of x and y

x=2   y=5                          // As both conditions i.e ( x>0 and y>0) are True so statement is executed

point(2,5) lies in Ist quad 

Output2:

Enter the value of x and y

x=2   y=-6                         // As both conditions i.e ( x>0 and y<0) are True so statement is executed

point(2,-6) lies in IVth quad 

 

Output3:

Enter the value of x and y

x=0   y=0                          // As both conditions i.e ( x=0 and y=0) are True so statement is executed

point(0,0) lies at the origin 

 

Posted by Roky

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